ĸܶΪf(x,y)=12y^2

(X,Y)f(x,y)={12y^2,0(X,Y)f(x,y)={12y^2,0(X,Y)f(x,y)={12y^2,0同学,我能写的就是这么多了.

f(x+y)=f(x)+f(y)+2xyf(x+y)=f(x)+f(y)+2xyf(x+y)=f(x)+f(y)+2xy游客1:定义在R上的函数f(x)满足f(x+y)=f(x)+f(y)+2xy(x

f(xy,x-y)=x^2+y^2+xy;f(x,y)/∂x;f(x,y)/∂yf(xy,x-y)=x^2+y^2+xy;f(x,y)/∂x;f(x,y)/W

f(x+Y)+f(x-y)=2f(x)f(Y)求其是偶函数急f(x+Y)+f(x-y)=2f(x)f(Y)求其是偶函数急f(x+Y)+f(x-y)=2f(x)f(Y)求其是偶函数急令y=-x,代入,f

求证f（x+y）+f(x-y)=2f(x)f(y)是周期函数求证f（x+y）+f(x-y)=2f(x)f(y)是周期函数求证f（x+y）+f(x-y)=2f(x)f(y)是周期函数首先f(x)=0肯定

设f(x+y,x-y)=x^2-y^2,则f(x,y)=设f(x+y,x-y)=x^2-y^2,则f(x,y)=设f(x+y,x-y)=x^2-y^2,则f(x,y)=f(x+y，x-y)=x

若f(x+y,y/x)=x^2-y^2,则F(X,Y)=若f(x+y,y/x)=x^2-y^2,则F(X,Y)=若f(x+y,y/x)=x^2-y^2,则F(X,Y)=令X=x+y,Y=y/x,解得x

已知f(x+y,y/x)=x^2-y^2,则f(x,y)=已知f(x+y,y/x)=x^2-y^2,则f(x,y)=已知f(x+y,y/x)=x^2-y^2,则f(x,y)=令m=x+yn=y/x代入

f(x+y,x-y)=(x^2-y^2)/2xy,求f(x,y)!f(x+y,x-y)=(x^2-y^2)/2xy,求f(x,y)!f(x+y,x-y)=(x^2-y^2)/2xy,求f(x,y)!1

f(x+y,y/x)=x^2-y^2求f(x,y)f(x+y,y/x)=x^2-y^2求f(x,y)f(x+y,y/x)=x^2-y^2求f(x,y)令x+y=t,y/x=u则y=xu代入x+y=t,

f(x+y,y/x)=x^2-y^2,求f(x,y),详见里面f(x+y,y/x)=x^2-y^2,求f(x,y),详见里面f(x+y,y/x)=x^2-y^2,求f(x,y),详见里面设u=x+y,

f(x+y,x-y)=2xy(x-y),求f(x,y)f(x+y,x-y)=2xy(x-y),求f(x,y)f(x+y,x-y)=2xy(x-y),求f(x,y)f(x+y,x-y)=(1/2)[(x

设f(x)=e的y次方,证明：（1）,f(x)f(y)=f(x+y),(2),f(x)/f(y)=f(x-y)设f(x)=e的y次方,证明：（1）,f(x)f(y)=f(x+y),(2),f(x)/f

已知F(X+Y,X-Y)=X^2*Y+X*Y^2,则F(X,Y)=?已知F(X+Y,X-Y)=X^2*Y+X*Y^2,则F(X,Y)=?已知F(X+Y,X-Y)=X^2*Y+X*Y^2,则F(X,Y)

f(x^2-y^2,x-y)=x+y+x^2-xy,求f''(x,y)对y求导f(x^2-y^2,x-y)=x+y+x^2-xy,求f''(x,y)对y求导f(x^2-y^2,x-y)=x+y+x^2-x

设f(x+y,x-y)=x^2+y^2-x*y求f(x,y)设f(x+y,x-y)=x^2+y^2-x*y求f(x,y)设f(x+y,x-y)=x^2+y^2-x*y求f(x,y)答：f(x+y,x-

已知f(x)=3^x,求证：(1)f(x)·f(y)=f(x+y);(2)f(x)/f(y)=f(x-y).已知f(x)=3^x,求证：(1)f(x)·f(y)=f(x+y);(2)f(x)/f(y)

f(x+y)+f(x-y)=2f(x)cosy,求证f(x)为周期函数f(x+y)+f(x-y)=2f(x)cosy,求证f(x)为周期函数f(x+y)+f(x-y)=2f(x)cosy,求证f(x)

设f(x+y,x-y)=x^2+xy,求f(x,y)设f(x+y,x-y)=x^2+xy,求f(x,y)设f(x+y,x-y)=x^2+xy,求f(x,y)设f(x+y,x-y)=x^2+xy设u=x

f(x+y)+f(xy-1)=f(x)f(y)+2f(n)表达式f(x+y)+f(xy-1)=f(x)f(y)+2f(n)表达式f(x+y)+f(xy-1)=f(x)f(y)+2f(n)表达式求什么设