(1)(x+y+z)(x-y-z)= (2)2012^2-2014×201=
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(1)(x+y+z)(x-y-z)= (2)2012^2-2014×201=
(1)(x+y+z)(x-y-z)= (2)2012^2-2014×201=
(1)(x+y+z)(x-y-z)= (2)2012^2-2014×201=
1)(x+y+z)(x-y-z)= x^2-y^2-z^2-2yz
2)2012^2-2014×2010=2012^2-(2012+2)×(2012-2)=4
已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=?
已知实数X.Y.Z满足(Y+Z)分之X+(Z+X)分之Y+(X+Y)分之Z=1,则(Y+Z)分之X平方+(Z+X)分之Y平方+(X+Y)分之Z平方的值为( )
(x+y-z)(x-y+z)=
x分之y+z=y分之z+x=z分之x+y(x+y+z不等于0),求x+y+z分之x+y-z
分式加减法:已知x+y/z=x+z/y=y+z/x(x+y+z≠0),求x+y-z/x+y+z
已知x+y/z=x+z/y=y+z/x(x+y+z≠0),求x+y-z/x+y+z的步骤
已知x+y/z=x+z/y=y+z/x(x+y+z≠0),求x+y-z/x+y+z的步骤
1.设有比例式:x/(y+z)=y/(x+z)=z/(x+y),有比例性质,得x/(y+z)=y/(x+z)=z/(x+y)=(x+y+z)/[(y+z)+(x+z)+(x+y)]=0.5x/(y+z)=y/(x+z)=(x-y)/[(y+z)-(x+z)]=-1,由此可得0.5=-1试分析推理产生错误的原因
(x-y-z)*( )=x²-(y-z)²
已知x,y,z>0,xyz(x+y+z)=1,求证(x+y)(x+z)>=2
(x+y+z)*(-x+y+z)*(x-y+z)*(x+y-z)=
X+Y+Z=?
(x+y-z)(x-y+z)-(x+y+z)(x-y-z)
x/y=(x+z)/(y+z)y/z=(x+y)/(x+z)
(x+y-z)*(x+y-z)-(x-y+z)*(x-y-z)等于多少
(x+y+z)(x-y+z)+(y-x+z)(y-x-z)求过程
(x-y+z)(-x+y+z)=[z+( )][ ]=z²-( )²
{x+y-z=11 y+z-x=5 z+x-y=1