1.若4x+3-3x-2=0,则x^2005=___2.已知a-b=0,则〔a^4+a^3b+a^2b^2+ab^3+b^4]/a^2b^2= 3.若1

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1.若4x+3-3x-2=0,则x^2005=___2.已知a-b=0,则〔a^4+a^3b+a^2b^2+ab^3+b^4]/a^2b^2= 3.若1

1.若4x+3-3x-2=0,则x^2005=___2.已知a-b=0,则〔a^4+a^3b+a^2b^2+ab^3+b^4]/a^2b^2= 3.若1
1.若4x+3-3x-2=0,则x^2005=___
2.已知a-b=0,则〔a^4+a^3b+a^2b^2+ab^3+b^4]/a^2b^2=
3.若1

1.若4x+3-3x-2=0,则x^2005=___2.已知a-b=0,则〔a^4+a^3b+a^2b^2+ab^3+b^4]/a^2b^2= 3.若1
1.4x+3-3x-2=0
x=-1
所以x^2005=-1
2.a-b=0
a=b
代入 得到结果为5
3.1

(1)-1
(3)2