(20/x+y)-(10/x-y)=1 求解

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(20/x+y)-(10/x-y)=1 求解

(20/x+y)-(10/x-y)=1 求解
(20/x+y)-(10/x-y)=1 求解

(20/x+y)-(10/x-y)=1 求解
两个未知数,一个算式,这怎么解?猜?

y(x+y)+(x-y)²-(x+y)(x-y),其中x=-1/3,y=3 1.5(x+y)+3(x-y)=27(x+y)-3(x-y)=-62.x-y/7 - x+y/10 =1/22(x-y)-5(x+y)=3所谓细节决定成败, 集合N={(x,y)|(x-1)^2}+(y-1)^20},M={(x,y)|x^2+y^2 10/x+y+3/x-y=-5 15/x+y-2/x-y=-1(用换元法解此方程组) 若(5x+y)/(7x+10y)=1/2则x/y= [(2x+3y)²-(y+2x)(2x-y)-10y(x+y+1)÷2y其中x=2019,y=20 1.4(x-y-1)=3(1-y)-22/x+3/y=22.5(x+y)-6=43x+3y+7y=10 方程组:x(y+1)+2(y+1)=y(y-1)x-5(y-1) x(4+y)-y(8-x)=-20x(y+1)+2(y+1)=y(y-1)x-5(y-1) x(4+y)-y(8-x)=-20(这是一个方程组.) 分式的加减:[(x/y-y/x)除以(x+y)+x(1/y-1/x)]除以1+x/y,其中x=5,y=2 对于(y一撇)y`=y/x(y-1)求导,我求的结果是y``=-y^2-y`x+y/x^2(y-1)^2 怎么不对啊,我的求导过程是:y`x(y-1) - [x(y-1)]` y y`xy-y`x-(y-1+xy`)y -y^2-y`x+yy``=-------------------------=----------------------=-----------------x^2 (y-1 5(x-y)³-3(x-y)²+7(x-y)-5(x-y)³+(x-y)²-5(x-y),其中,x-y=1/3.5(x-y)³-3(x-y)²+7(x-y)-5(x-y)³+(x-y)²-5(x-y),其中,x-y=1/3先化简,再求值; 解下列方程 {x+y=9 (1) {(10y+x)-(10x+y)=9 (2){(10x+y)-3(x+y)=23 (1){5(x+y)+1=10x+y (2){x+y=9 (1){(10y+x)-(10x+y)=9 (2) {(10x+y)-3(x+y)=23 (1){5(x+y)+1=10x+y (2) y=2x*(*代表X)y=(lnx)*y=(x/1+X)* 先化简,再求值 (1)[(x-y)的平方+(x+y)(x-y)]÷2x 其中X=2010,y=2009 (2)y(x+y)+(x+y)(x-y)-x的平方,先化简,再求值(1)[(x-y)的平方+(x+y)(x-y)]÷2x 其中X=2010,y=2009(2)y(x+y)+(x+y)(x-y)-x的平方,其中x=-2,y=二分 若x+y=4,则多项式1/2(x+y)+4(x-y)-3(x-y)-3/2(x+y)-x+y值是() 若|x+y-1|+(x-y-2)²=0,求代数式(x+2y)(x-2y)-(2x-y)(-y-2x)的值. 【(x-y)的平方+(x-y)(x+y)】除以x,其中x= -1 y=二分之一 3(x-1)³y-(1-x)³z m(x-y)²-x+y x²(x+y)(y-x)-xy(x+y)(x-y) 因式分解