a、b为实数,且ab=1,设P=a/(a+1)+b/(b+1),Q=1/(a+1)+1/(b+1)则P()Q

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a、b为实数,且ab=1,设P=a/(a+1)+b/(b+1),Q=1/(a+1)+1/(b+1)则P()Q

a、b为实数,且ab=1,设P=a/(a+1)+b/(b+1),Q=1/(a+1)+1/(b+1)则P()Q
a、b为实数,且ab=1,设P=a/(a+1)+b/(b+1),Q=1/(a+1)+1/(b+1)
则P()Q

a、b为实数,且ab=1,设P=a/(a+1)+b/(b+1),Q=1/(a+1)+1/(b+1)则P()Q
p-q
=a/(a+1)+b/(b+1)-1/(a+1)-1/(b+1)
=(a-1)/(a+1) +(b-1)/(b+1)
=(a-1)/(a+1) +(1/a -1)/(1/a +1) b=1/a
=(a-1)/(a+1)+(1-a)/(a+1)
=0
∴p=q

答案是P=Q