已知x/3=y/5=z/6,求3x-2y+z/2x+y+2z的值

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已知x/3=y/5=z/6,求3x-2y+z/2x+y+2z的值
已知x/3=y/5=z/6,求3x-2y+z/2x+y+2z的值

已知x/3=y/5=z/6,求3x-2y+z/2x+y+2z的值
设x/3=y/5=z/6=k.
则:x=3k,y=5k,z=6k.
故原式=(3*3k -2*5k +6k)/(2 *3k + 5k + 2*6k)
=(9k -10k +6k) /(6k +5k +12k)
=5k/(23k)
=5/23

设x/3=y/5=z/6=k，这样x=3k,y=5k,z=6k,带入消去k得
3x-2y+z/2x+y+2z=5/23

设x/3=y/5=z/6=k
x=3k, y=5k, z=6k
将以上值代入：
3x-2y+z/2x+y+2z
=(9k-10k+6k)/(6k+5k+12k)
=(5k)/(23k)
=5/23

简单解答:设x/3=y/5=z/6=k 则x=3k,y=5k,z=6k.代入后式：(9k-10k+6k)/(6k+5k+12k)=5/23

令 x/3=y/5=z/6=k
x=3k y=5k z=6k
3x-2y+z/2x+y+2z
=9k-10k+6k/6k+5k+12k
=16k+1
=16/3 x+1

三个答案:1+16*X/3
或:1+16*Y/5
或:1+16*Z/6
我觉得你给的题可能写错了.

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