求4x^2y-{6xy-2(4xy-2)-x^2y}+1的值,其中x=-1/2,y=1

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/08 22:37:18
求4x^2y-{6xy-2(4xy-2)-x^2y}+1的值,其中x=-1/2,y=1

求4x^2y-{6xy-2(4xy-2)-x^2y}+1的值,其中x=-1/2,y=1
求4x^2y-{6xy-2(4xy-2)-x^2y}+1的值,其中x=-1/2,y=1

求4x^2y-{6xy-2(4xy-2)-x^2y}+1的值,其中x=-1/2,y=1
原式=4x^2y-(6xy-8xy+4-x^2y)+1
=4x^2y-(-2xy+4-x^2y)+1
=4x^2y+2xy-4+x^2y+1
=5x^2y+2xy-3
=5*1/4*1+2*(-1/2)*1-3
=5/4-1-3
=-15/4