Log(2)(x+2)+log(2)(x-2)=5这里2是底数,(怕大家看不清楚^-^)
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Log(2)(x+2)+log(2)(x-2)=5这里2是底数,(怕大家看不清楚^-^)
Log(2)(x+2)+log(2)(x-2)=5
这里2是底数,
(怕大家看不清楚^-^)
Log(2)(x+2)+log(2)(x-2)=5这里2是底数,(怕大家看不清楚^-^)
知识点:
(1) log(a)(m)+log(a)(n)=log(a)(mn)
(2) 若log(a)(m)=b,则a^b=m
由已知得,x+2>0,x-2>0 => x>2
原式=log(2)(x+2)(x-2)=log(2)(x^2-4)=5
∴2^5=x^2-4
∴x=-6(舍),x=6
综上所述x=6
原式等价于
Log(2) [(x+2)/(x-2)]=5 {x-2>0}
即[(x+2)/(x-2)]=2^5
解得x=(2^5+2)/(2^5-2)
此时x-2<0,Log(x-2)无意义
此题无实解
由题:Log(2)(x+2)+log(2)(x-2)=5
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x^=36
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