作业帮化简:{[-b+根号(b²-4ac)]/2a}*{[-b-根号(b²-4ac)]/2a }(b²≥4ac)
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/30 03:23:46
![化简:{[-b+根号(b²-4ac)]/2a}*{[-b-根号(b²-4ac)]/2a }(b²≥4ac)](/uploads/image/z/5296893-69-3.jpg?t=%E5%8C%96%E7%AE%80%3A%7B%5B-b%2B%E6%A0%B9%E5%8F%B7%28b%26%23178%3B-4ac%29%5D%2F2a%7D%2A%7B%5B-b-%E6%A0%B9%E5%8F%B7%28b%26%23178%3B-4ac%29%5D%2F2a+%7D%28b%26%23178%3B%E2%89%A54ac%29)
化简:{[-b+根号(b²-4ac)]/2a}*{[-b-根号(b²-4ac)]/2a }(b²≥4ac)
化简:{[-b+根号(b²-4ac)]/2a}*{[-b-根号(b²-4ac)]/2a }(b²≥4ac)
化简:{[-b+根号(b²-4ac)]/2a}*{[-b-根号(b²-4ac)]/2a }(b²≥4ac)
:{[-b+根号(b²-4ac)]/2a}*{[-b-根号(b²-4ac)]/2a }
=1/(4a)×[b²-(b²-4ac)]
=1/(4a)×4ac
=c/a
这个是两根之积啊
结果等于c/a
这题结果就是：c/a