lim[1/n(1+1/2)(1+1/3)……(1+1/n)]如题,到底是那个对啊？怎么出来的呢？

lim(n+3)(4-n)/(n-1)(3-2n) lim(n^3+n)/(n^4-3n^2+1) lim[(n+3)/(n+1))]^(n-2) 【n无穷大】 lim(2^n+3^n)^1 (n趋向无穷) 求1.lim(3n-(3n^2+2n)/(n-1)) 2.lim(8+1/(n+1)) 3.lim根号n(根号(n+1)-根号(n-3)) lim n->无穷大(2^n-1)/(3^n+1) lim根号n^2+n+1/3n-2 lim根号n^2+n+1/3n-2=? 求lim n→∞ (1+2/n)^n+3 lim(n→∞)[1-(2n/n+3)] lim(3^2n+5^n)/(1+9^n)=? lim(n→∞)(2n-1/n+3) lim[(4+7+...+3n+1)/(n^2-n)]= lim(1/n+2/n+3/n+4/n+5/n+……+n/n)=lim(1/n)+lim(2/n)+……+lim(n/n)成立吗?（n趋近于无穷大）为什么不成立? 高数 lim n趋向无穷 lim（3^(1/n)-1)ln(2+2^n) 求极限lim 2/(3^n-1) lim(1-1/n)^(n^2)=? lim(1-1/n^2)^n=?