cos(α +2π/3)=1/6,则cos(2α-2π/3)

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cos(α +2π/3)=1/6,则cos(2α-2π/3)

cos(α +2π/3)=1/6,则cos(2α-2π/3)
cos(α +2π/3)=1/6,则cos(2α-2π/3)

cos(α +2π/3)=1/6,则cos(2α-2π/3)
cos(a-π/3)=cos(a+2π/3-π)=√35/36 原式=cos【2(a-π/3)]=35/18-1=17/18