作业帮y=3sin(π/6-3x),x∈[-π/2,π.2]的单调增区间是
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![y=3sin(π/6-3x),x∈[-π/2,π.2]的单调增区间是](/uploads/image/z/7016014-46-4.jpg?t=y%3D3sin%28%CF%80%2F6-3x%29%2Cx%E2%88%88%5B-%CF%80%2F2%2C%CF%80.2%5D%E7%9A%84%E5%8D%95%E8%B0%83%E5%A2%9E%E5%8C%BA%E9%97%B4%E6%98%AF)
y=3sin(π/6-3x),x∈[-π/2,π.2]的单调增区间是
y=3sin(π/6-3x),x∈[-π/2,π.2]的单调增区间是
y=3sin(π/6-3x),x∈[-π/2,π.2]的单调增区间是
因为：y=3sin(π/6-3x)
所以：y'=3cos(π/6-3x)(-3)=-9cos(π/6-3x)
令：y'≥0,有：
-9cos(π/6-3x)≥0
cos(π/6-3x)≤0
所以：3π/2≥π/6-3x≥π/2
解得：-4π/9≤x≤π/9
即：单调增区间是：x∈(-4π/9,π/9)
-π/2<=x<=π/2
-3π/2<=3x<=3π/2
-3π/2<=-3x<=3π/2
π/6-3π/2<=π/6-3x<=3π/2+π/6
-4π/3<=π/6-3x<=5π/3
单调增区间：-π/2<=π/6-3x<=π/2
-π/2<=3x-π/6<=π/2
-π/3<=3x<=2π/3
-π/9<=x<=2π/9
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