如图,已知AB=AE,BC=ED,AC=AD,求证:BE平行CD

已知：如图,AE⊥AB,BC⊥AB,AE=AB,ED=AC.求证：ED⊥AC. 已知：如图,AE⊥AB,BC⊥AB,AE=AB,ED=AC 求证：ED⊥AC 已知,如图,ae垂直ab,bc垂直ab,ae=ab,ed=ac 求证 ed垂直ac 如图,已知：AB=AE,AC=AD,AC⊥AD,AB⊥AE.求证：ED⊥BC. 如图,已知AB=AE,BC=ED,AC=AD,求证:BE平行CD 如图,已知AE=AD,AB=AC,求证ED⊥BC 如图,AE⊥AB,BC⊥AB,AE=AB,ED=AC,求证:ED⊥AC 已知,如图,AB⊥BC,AE⊥ED,AB=AE, 已知:如图,AB⊥BC,AE⊥ED,AB=AE, 已知：如图,AD=BC,AC=ED,AB=AE, 求证： 角ACD=角ADC 如图,已知AB分之AE = BC分之ED = AC分之AD 证明∠BAD=∠CAE 如图AB=AE,AC=AD,ED=BC,AE⊥AB 求证BC⊥DE 已知;如图,ae⊥ab,bc⊥ab,ae==ba,ed=ac.求证：△ead全等于△abc 如图:AB=AC,ED=EC,△ABC∽△EDC求证:AE//BC 如图,AB=AE.BC=ED. 如图,AB=AE.BC=ED. 如图,AE⊥AB,BC⊥AB,CD⊥ED,ED=DC.求证：AE+BC=AB. 已知：如图AE垂直AB,BC垂直AB,AE=AB,ED=AC,求证：ED垂直于AC因为AE⊥AB,BC⊥AB,所以角EAB=角B=90度.又因为AE=AB,ED=AC ,所以△AED全等于△ABC.所以∠CAB=∠E.又因为∠E+∠ADE=90°,所以∠CAB+∠ADE=90°,即ED⊥AC（