matlab中出现?In an assignment A(I) = B,the number of elements in B and I must be the same.clear;R=5;Z=2*pi*R;Lambda=300;c=3*10^8;Omega=1:10;for g=1:length(Omega)Phi(g)=4*pi*R*Z*Omega(g)/(Lambda*c);T1=[sqrt(1/2) 1i*sqrt(1/2);1i*sqrt(1/2) sqrt(1/2)]

matlab中出现?In an assignment A(I) = B,the number of elements in B and I must be the same.clear;R=5;Z=2*pi*R;Lambda=300;c=3*10^8;Omega=1:10;for g=1:length(Omega)Phi(g)=4*pi*R*Z*Omega(g)/(Lambda*c);T1=[sqrt(1/2) 1i*sqrt(1/2);1i*sqrt(1/2) sqrt(1/2)]
matlab中出现?In an assignment A(I) = B,the number of elements in B and I must be the same.
clear;
R=5;
Z=2*pi*R;
Lambda=300;
c=3*10^8;
Omega=1:10;
for g=1:length(Omega)
Phi(g)=4*pi*R*Z*Omega(g)/(Lambda*c);
T1=[sqrt(1/2) 1i*sqrt(1/2);1i*sqrt(1/2) sqrt(1/2)];
T2(g)=[1 0;0 exp(1i*Phi(g))];
B=[1;0];
A(g)=T1*T2(g)*T1*B;
E1=A(1,1);
E2=A(2,1);
P1=E1^2;
P2=E2^2;
end
plot(Lambda,P1,Lambda,P2);
title('角速度与输出功率的关系');
xlabel('角速度');
ylabel('输出功率');

matlab中出现?In an assignment A(I) = B,the number of elements in B and I must be the same.clear;R=5;Z=2*pi*R;Lambda=300;c=3*10^8;Omega=1:10;for g=1:length(Omega)Phi(g)=4*pi*R*Z*Omega(g)/(Lambda*c);T1=[sqrt(1/2) 1i*sqrt(1/2);1i*sqrt(1/2) sqrt(1/2)]
不明白你最后的plot是什么目的,肯定是画不出东西的,不过你提出的错误主要由于这里：T2(g)=[1 0;0 exp(1i*Phi(g))]; T2若是一个矩阵,就不能加（g）成为集合的集合,何况T2、A只是作为中间变量,没有必要带序号.完全可以用中间变量代替,全码小改动：
clear;
R=5;
Z=2*pi*R;
Lambda=300;
c=3*10^8;
Omega=1:10;
l=length(Omega);
for g=1:l %length(Omega)
x=4*pi*R*Z*Omega(g)/(Lambda*c); %Phi(g)=4*pi*R*Z*Omega(g)/(Lambda*c);
y=exp(1i*x);
T1=[sqrt(1/2) 1i*sqrt(1/2);1i*sqrt(1/2) sqrt(1/2)];
T2=[1 0;0 y]; %T2(g)=[1 0;0 exp(1i*Phi(g))];
B=[1;0];
A=T1*T2*T1*B; % A(g)=T1*T2(g)*T1*B;
E1=A(1,1);
E2=A(2,1);
P1=E1^2;
P2=E2^2;
end
plot(Lambda,P1,Lambda,P2);
title('角速度与输出功率的关系');
xlabel('角速度');
ylabel('输出功率');
%%最后plot命令不是这么用,也不明白你的意思,还要在改动才能画出你要的东西.问题解决.

你是中南材料的？？

clear;
R=5;
Z=2*pi*R;
Lambda=300;
c=3*10^8;
Omega=1:10;
l=length(Omega);
for g=1:l %length(Omega)
x=4*pi*R*Z*Omega(g)/(Lambda*c); %Phi(g)=4*pi*R*Z*Omega(g)/(Lamb...

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clear;
R=5;
Z=2*pi*R;
Lambda=300;
c=3*10^8;
Omega=1:10;
l=length(Omega);
for g=1:l %length(Omega)
x=4*pi*R*Z*Omega(g)/(Lambda*c); %Phi(g)=4*pi*R*Z*Omega(g)/(Lambda*c);
y=exp(1i*x);
T1=[sqrt(1/2) 1i*sqrt(1/2);1i*sqrt(1/2) sqrt(1/2)];
T2=[1 0;0 y]; %T2(g)=[1 0;0 exp(1i*Phi(g))];
B=[1;0];
A=T1*T2*T1*B; % A(g)=T1*T2(g)*T1*B;
E1=A(1,1);
E2=A(2,1);
P1=E1^2;
P2=E2^2;
end
plot(Lambda,P1,Lambda,P2);
title('角速度与输出功率的关系');
xlabel('角速度');
ylabel('输出功率');

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