化简√3(√2-√3)-√24-I√6-3I
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化简√3(√2-√3)-√24-I√6-3I
化简√3(√2-√3)-√24-I√6-3I
化简√3(√2-√3)-√24-I√6-3I
化简√3(√2-√3)-√24-I√6-3I
(-1+√3i)^3/(1+i)^6+(-2+i)/(1+2i)的值是
((-1+√3i)^3/(1+i)^6)-((-2+i)/(1+2i))过程怎么写
计算((-1+√3i)^3/(1+i)^6)+((-2+i)/(1+2i))
I1-√2I+I√2-√3I+I√3-2I+I2-√5I+.+I√2010-√2011I
(-√3/2-i/2)^12+[(2+2i)/(1-i√3)]^8
(1+√ 3i)3/(1+i)6- -2+i/1+2i的值 需要详细的过程
(3i/√2-i)^2的虚部是多少?是(根号2)-i
计算[(1-3i)^15-(1+3i)^6]/[2i(-1+i)^12(1/2+1/2i)^4]上面的题目错了 是计算[(1-√3i)^15-(1+√3i)^6]/[2i(-1+i)^12(1/2+1/2i)^4]
计算(1)2+i分之(1+2i)+3(1-i);(2)(√3+i)分之1-√3i
[(1-√3i)^5-(1+√3i)^4]/[i*(-1+i^8)*(1/2+1/2i)]的答案是2√3-4i,
复数(1+√3i)/(√3-i)=
I√2-√3l-I1-√3I-I1+√2I
z=(3+4i)(√2-√2i)/(1/2-√3i)(-√3+i)求模长
(x-1-√2i)(x-1+√2i)(x-2+√3i)(x-2-√3i)
(3i/√2-i)^2的虚部是多少
计算或化简:(1)I1-√2I+I√2-√3I+I√3-2I;(2)³√6﹣π﹣2(精确到0.01)I1-√2I+I√2-√3I+I√3-2I;(2)³√6﹣π﹣2(精确到0.01)
计算(-√3/2-1/2i)^12+(2+2i/1-√3i)^8