化简sin(π/4-α)+cos(π/4+α)

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/02 13:07:15
化简sin(π/4-α)+cos(π/4+α)

化简sin(π/4-α)+cos(π/4+α)
化简sin(π/4-α)+cos(π/4+α)

化简sin(π/4-α)+cos(π/4+α)
sin(π/4-α)+cos(π/4+α)
=sin(π/4-α)+cos[π/2-(π/4-α)]
=sin(π/4-α)+sin(π/4-α)
=2sin(π/4-α)

化简sin(π/4+α)cosα-sin(π/4-α)sinα 化简sin(α-5π)/cos(3π-α)×cos(π/2-α)/sin(α-3π)×cos(8π-α)/sin(-α-4π) 化简sin(α-2π)+sin(-a-3π)cos(α-3π)/cos(π-α)-cos(-π-α)cos(α-4π) 化简sin(π/4-α)+cos(π/4+α) 化简【cos(π/4+α)-sin(π/4+α)】/【cos(π/4-α)+sin(π/4-α)】.如题 化简:sin(π/4-α)cos(π/3-α)-cos(π/6+α)sin(π/4+α)= 化简:[1+2sin(α+2π)*cos(α-2π)]/[sin(α+4π)+cos(α+8π)] 利用和差角公式化简 (2)sin(π/3+α)+sin(π/3-α)(2)sin(π/3+α)+sin(π/3-α)(3)cos(π/4+α)-cos(π/4-α)(4)cos(60°+α)+cos(60°-α)(5)sin(α-β)cosβ+cos(α-β)sinβ(6)cos(α+β)cosβ+sin(α+β)sinβ cos^2(π/4+α)=(cos(π/4)cosα-sin(π/4)sinα)² cos^2(π/4+α)是怎么等于(cos(π/4)cosα-sin(π/4)sinα)²的? 化简:2cos²α-1/【2sin(π/4-α)sin²(π/4+α)】 化简:2cos²α-1/【2sin(π/4-α)sin²(π/4+α)】 求值:(tan10°-√3)×cos10°/sin50° 求证:[sin(2α+β)]/sinα- 2cos(α+β)=sinβ/cosα 化简cosθ+cos(θ+2π/3)+cos(θ+4π/3) 证明:sin(α+β)sin(α-β)=sin^2α-sin^2β 化简:cosα+sinα+a²sin(α+π/4) 化简 {sin(π+α)cos(α-2π)tan9π/4}/sin(-α)sin(7π/2+α)过程 化简sin(A+π/4)sin(A-π/4)/sin^4A-cos^4A 1.化简根号2cos x - 根号6sin x2.已知sin(α-β)cosα-cos(β-α)sinα=3/5,β是第三象限角,求sin(β+5π/4)的值.3.化简sin(α-β)sin(β-λ)-cos(α-β)cos(λ-β) 已知0<α<π/2,且3sinα=4cosα求(sin^2α+2sinαcosα)/(3cos^2α-1)求cos^2α+sinαcosα 已知sinα+cosα=4/5且3π/22,若sinα+sinβ+sinγ=0,cosα+cosβ+cosγ=0,则cos(α-β)的值