|α1,α2,α3| = a 1 1 1 a -1 1 -1 a = (a - 2)(a + 1)^2.是怎么得到等号后面的,|α1,α2,α3| =a 1 11 a -11 -1 a= (a - 2)(a + 1)^2.

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|α1,α2,α3| = a 1 1 1 a -1 1 -1 a = (a - 2)(a + 1)^2.是怎么得到等号后面的,|α1,α2,α3| =a 1 11 a -11 -1 a= (a - 2)(a + 1)^2.

|α1,α2,α3| = a 1 1 1 a -1 1 -1 a = (a - 2)(a + 1)^2.是怎么得到等号后面的,|α1,α2,α3| =a 1 11 a -11 -1 a= (a - 2)(a + 1)^2.
|α1,α2,α3| = a 1 1 1 a -1 1 -1 a = (a - 2)(a + 1)^2.是怎么得到等号后面的,
|α1,α2,α3| =
a 1 1
1 a -1
1 -1 a
= (a - 2)(a + 1)^2.

|α1,α2,α3| = a 1 1 1 a -1 1 -1 a = (a - 2)(a + 1)^2.是怎么得到等号后面的,|α1,α2,α3| =a 1 11 a -11 -1 a= (a - 2)(a + 1)^2.
行列式的值你不会求吗?对角线相乘.这是笨法
还可以先化简: