作业帮(cos π/8+ sin π/8 ) (cos^3 π/8+sin^3 π/8 )的值.
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/29 14:12:34
(cos π/8+ sin π/8 ) (cos^3 π/8+sin^3 π/8 )的值.
(cos π/8+ sin π/8 ) (cos^3 π/8+sin^3 π/8 )的值.
(cos π/8+ sin π/8 ) (cos^3 π/8+sin^3 π/8 )的值.
(cos π/8+ sin π/8 ) (cos^3 π/8+sin^3 π/8 )
=[(cos π/8+ sin π/8 )^2] (cos^2 π/8-cosπ/8sinπ/8+sin^2 π/8 )
=(1+2cos π/8 sin π/8 ) (1-cosπ/8sinπ/8 )
=(1+sin π/4 ) [1-(1/2)sinπ/4]
=(1+√2/2) [1-(1/2)√2/2]
=(1+√2/2) (1-√2/4)
=(3+√2)/4
求SINπ/64 COSπ/64 COSπ/32 COSπ/16 COSπ/8
sinπ/8×cosπ/8
sinπ/8×cosπ/8
sinπ/8*cosπ/8
sinπ/8cosπ/8=( )
(cosπ/8+sinπ/8)（cos^3π/8-sin^3π/8）
(cosπ/8+sinπ/8)（cos^3π/8-sin^3π/8）.
(cos π/8+ sin π/8 ) (cos^3 π/8+sin^3 π/8 )的值.
cos 5π/8 cos π/8 + sin 5π/8 sin π/8=
8sin(π/32)cos(π/32)cos(π/16)cos(π/8),求值
求SINπ/64 COSπ/64 COSπ/32 COSπ/16 COSπ/8!急救急救
化简sin(α-5π)/cos(3π-α)×cos(π/2-α)/sin(α-3π)×cos(8π-α)/sin(-α-4π)
cos^6(π/8)-sin^6(π/8)=求值,[cos^2(π/8)-sin^2(π/8)][cos^4(π/8)+sin^4(π/8)+cos^2(π/8)sin^2(π/8)]=cos(π/4)[1-cos^2(π/8)sin^2(π/8)]=cos(π/4)[1-[sin^2(π/4)]/4]==7√2/16
计算sin²π/8-cos²π/8=
cos平方π/8-sin平方π/8,
sin²π/8 -cos²π/8
sin^4π/8 +cos^4π/8
(cos(π/8))^4-(sin(π/8))^4