+3,-3.5,0,π,2,11/4,-12,32.3,负二又十三分之三其中分数集合： 整数集合： 负数集合：

+3,-3.5,0,π,2,11/4,-12,32.3,负二又十三分之三其中分数集合： 整数集合： 负数集合： 指出下列各点所在的象限或坐标轴A(-3.5,-2)B(-4,3)C(5,6)D(12,-1)E(11,0)F(0,-4分之3）G（-2π,0）H（0,7.1） 求值:cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11) 求值：cos(π/11)-cos(2π/11)+cos(3π/11)-cos(4π/11)+cos(5π/11) cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11) 关于弧度制的一些问题把下列的各角化为0到2π的角加上2kπ(k∈Z)的形式:(1) -25π/6 (2) -5π (3)-64° (4) 400° (1) -25π/6=(-36π/6+11π/6)=2*(-3)π+11π/6所以-25π/6可写为2kπ+11π/6(k∈Z) 疑惑:-36π/6+11π/6 是怎么 cos（π/11）cos（2π/11）cos（3π/11）cos（4π/11）cos（5π/11）怎么解 2sin^225/4π+tan^2(-11/3π)*cot(-7/4π) 求cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)求值:cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)(5/24)(11/24)=5/11?,而且过程和题好像都没关系。 0-5之间11个数字选三个数除以3哪个数概率最大0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 sin0=0 sin(1/6π)=1/2sin(1/3π)=√3/2sin(1/2π)=1sin(2/3π)=√3/2sin(5/6π)=1/2sin(π)=0sin(-π)=0sin(-5/6π)=-1/2sin(-2/3π)=-√3/2sin(-1/2π)=-1sin(-1/3π)=-√3/2sin(-1/6π)=-1/2sin(7/6π)=-1/2sin(4/3π)=-√3/2sin(5/3π)=-√3/2sin(11/6π)=-1/ 分类 -7 3.5 π 0 13/17 0.03 -3右1/2 10 -0.23 二三的循环 -4/2 自然数 整数 正分数 非正数 有理数 11-x+3/4x=3.5 计算4sin（2π/11）+tan（3π/11）要解法和答案 简算3.5*11/4+125%+11/2÷5/4 简算3.5*11/4+125%+11/2÷5/4 (1) (-8)+10+2+(-1) =2+2+(-1) =4+(-1) =3 (2) 5+(-6)+3+9+(-4)+(-7) =(-1)+3+9+(-4)+(-7) =2+9+(-4)+(-7) =11+(-4)+(-7) =7+(-7) =0 (3) (-0.8)+1.2+(-0.7)+(-2.1)+0.8+3.5 =0.4+(-0.7)+(-2.1)+0.8+3.5 =(-0.3)+(-2.1)+0.8+3.5 =(-0.09)+0.8+3.5 =4.12 (4) 2/1+(-3/2)+ 三角函数求值：4Sin(2π/11)+tan(3π/11) ( π 是pai )请勿使用计算机得出答案