23X5/221/2-5/6X1/2(5/12-7/18)X363/4X8/9-1/37/9+7/9X85/8X7-5/8X3

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/06 03:14:46
23X5/221/2-5/6X1/2(5/12-7/18)X363/4X8/9-1/37/9+7/9X85/8X7-5/8X3

23X5/221/2-5/6X1/2(5/12-7/18)X363/4X8/9-1/37/9+7/9X85/8X7-5/8X3
23X5/22
1/2-5/6X1/2
(5/12-7/18)X36
3/4X8/9-1/3
7/9+7/9X8
5/8X7-5/8X3

23X5/221/2-5/6X1/2(5/12-7/18)X363/4X8/9-1/37/9+7/9X85/8X7-5/8X3
23X5/22
=115/22(五又二十二分之五)
1/2-5/6X1/2
=1/2×(1-5/6)
=1/2×1/6
=1/12
5/12-7/18)X36
=5/12×36-7/18×36
=15-14
=1
3/4X8/9-1/3
=2/3-1/3
=1/3
7/9+7/9X8
=7/9×(1+8)
=7/9×9
=7
5/8X7-5/8X3
=5/8×(7-3)
=5/8×4
=5/2
=2.5

最后一题等于5/2

23X5/22=(1+22)X5/22=5/22+5=5又5/22
1/2-5/6X1/2=(1-5/6)X1/2=1/12
(5/12-7/18)X36=5/12X36-7/18X36=15-14=1
3/4X8/9-1/3=2/3-1/3=1/3
7/9+7/9X8=7/9(1+8)=7
5/8X7-5/8X3=5/8(7-3)=5/2=2又1/2

解方程组:x1+x2+x3+x4+x5=7 3x1+2x2+x3+x4-3x5=-2 x2+2x3+2x4+6x5=23 5x1+4x2-3x3+3x4-x5=10 关于二元一次方程组若X1,X2,X3,X4,X5满足下列方程组:2X1+X2+X3+X4+X5=6X1+2X2+X3+X4+X5=12X1+X2+2X3+X4+X5=24X1+X2+X3+2X4+X5=48X1+X2+X3+X4+2X5=96则3X4+2X5的值是 多少?(X1,X2.X3.X4.X5的1.2.3.4.5不是乘除和加减,带表5个不同的 X1 - X3 - X4 -5X5=0 X1+2X2+3X3+3X4+7X5=0 X1+X2+X3+X4+X5=0 X2+2X3+2X4+6X5=0 解一道方程组x1+x2+x3=5,x2+x3+x4=1,x3+x4+x5=-5,x4+x5+x1=-3,x5+x1+x2=2 求解奇次线性方程组{上面2x1+x2+3x3+5x4-5x5 =0 中x1+x2+x3+4x4-3x5=0 下面3x1+x2+5x3+6x4-7x5=0 求方程组x1+3x2+x3+2x4+4x5=3 2x1-x2+8x3+7x4+2x5=9 4x1+5x2+6x3+11x4+10x5=15的全部解线性代数 请问方程组x1+x2-3x4-x5=0,x1-x2+2x3-x4+x5=0,4x1-2x2+6x3-5x4+x5=0的基础解系与通解怎么求 求解线性方程组 x1-2x2+3x3-x4-x5=2 x1+x2-x3+x4-2x5=1 2x1-求解线性方程组x1-2x2+3x3-x4-x5=2x1+x2-x3+x4-2x5=12x1-x2+x3-2x5=22x1+2x2-5x3+2x4-x5=5 matlab线性方程组计算X1+X2-5X3-X4+X5=98X1+5X2-X3+4X5=23X1-7X2-5X3-X4+X5=42X1+X2+8X3+3X4-X5=-86X2+2X3+7X4-2X5=15 求非其次线性方程组 {x1+2x2+x3+x4+x5=1x1+2x2+x3+x4+x5=12x1+4x2+3x3+x4+x5=2-x1-2x2+x3+3x4-x5=5 2x3+4x4-2x5=6 的一般解 x1-x2+x3=1 x2-x3+x4=2 x3-x4+x5=3 x4-x5+x1=4 x5-x1+x2=5 求x1,x2,x3,x4,x5 求下列非齐次线性方程组的通解(1){x1+x2+x3+x4+x5=2;x1+2x2-4x5=-2;x1+2x3+2x4+6x5=6;4x1+5x2+3x3+3x4-x5=4}(2){x1-x2+5x3-x4=1;x1+x2-2x3+3x4=1;2x1+3x3+2x4=2;2x1+4x2-11x3+10x4=2}(3){x1+x2+x3+x4+x5=1;3x1+2x2+x3+x4-3x5=0 上x1+x2+x3+4x4-3x5=0 中2x1+x2+3x3+5x4-5x5=0 中x1-x2+3x3-2x4-x5=0 下3x1+x2+5x3+6x4-7x5=0急, 判断下列奇次线性方程组是否有非零解?如果有,求其解.X1+X2+X3+4X4-3X5=0,X1-X2+3X3-2X4-X5=0,2X1+X2+3X3+5X4-5X5=0,3X1+X2+5X3+6X4-7X5=0 求齐次方程组的的一般解(x1+x2+x3+x4+x5=0,3x1+2x2+x3+x4-3x5=0,x1+2x3+2x4+6x5=0,5x1+4x2+3x3-x5=0) X1-2X2-X3+X4=02X1+X2-X3+2X4-3X5=03X1-2X2-X3+X4-X5=02X1-5X2+X3-2X4+2X5=0 23X5/221/2-5/6X1/2(5/12-7/18)X363/4X8/9-1/37/9+7/9X85/8X7-5/8X3 求非齐次线性方程组的通解x1+3x2+5x3-4x4=1x1+3x2+2x3-2x4+x5=-1x1-2x2+x3-x4-x5=3x1+2x2+x3-x4-x5=3