cos^3(-π-α)
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/06 10:10:44
cos^3(-π-α)
cos^3(-π-α)
cos^3(-π-α)
cos(-π-α) =-cosa
所以cos^3(-π-α) =-(cosa)^3
cos^3(-π-α) =cos^3(π-α) =[-cosα]^3=-(cosα)^3
cos^3(-π-α)
cos^2α+cos^2(α+π/3)-cosαcos(α+π/3)化简
cos(3π-α)=?
cos(α+5π/12)cos(α+π/6)+cos(π/12-α)cos(π/3-α) 化简
化简cos平方α+cos平方(α-π/3)+cos平方(α+π/3) 急、~
化简:cosα+cos(2π/3-α)+cos(2π/3+α)
【紧急求助】计算:cosα+cos(2π/3 +α)+cos(4π/3 +α)
求和:cos(0)+cos(α)+cos(2α)+cos(3α)+……cos(nα)
sin(3π+α )=1/4,求cos(π+α)/cosα[cos(π+α)-1]+cos(α-2π)/cos(α+2π)cos(π+α)+coa(-α)
求证:cosαcos(π/3+α)cos(π/3-α)=cos3α如题,求证:4cosαcos(π/3+α)cos(π/3-α)=cos3α不好意思 少打个4
化简sin(π/2+α)cos(3π-α)tan(π+α)/cos(π/2-α)cos(-α-π)
化简{sin(π+α)^3cos(-α)cos(π+α)}/{tan(π+α)^3cos(-π-α)^2}
不等式证明1已知α、β、γ∈(0,π/2),且tanα+tanβ+tanγ=3,求证:1/(cosαcosβ)+1/(cosβcosγ)+1/(cosγcosα)≥6.
(1+sinα+cosα)*[sin(α/2)-cos(α/2)]/√(2+2cosα)化简 (3/2*π
化简sin(α-2π)+sin(-a-3π)cos(α-3π)/cos(π-α)-cos(-π-α)cos(α-4π)
cos(3π-α)怎么化简
化简cos(α-3π)
化简:cos(-π-α)