(64-2x)(10-x)=558 (32-x)(20-x)=540

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(64-2x)(10-x)=558 (32-x)(20-x)=540

(64-2x)(10-x)=558 (32-x)(20-x)=540
(64-2x)(10-x)=558 (32-x)(20-x)=540

(64-2x)(10-x)=558 (32-x)(20-x)=540
(64-2x)(10-x)=558 ; 640-64x-20x+2x^2-558=0; 2x^2-84x+82=0; x^2-42x+41=0; (x-41)(x-1)=0; x-41=0,x=41;x-1=0,x=1 (32-x)(20-x)=540; 640-32x-20x+x^2-540=0; x^2-52x+100=0; (x-50)(x-2)=0; x-50=x,x=50; x-2=0,x=2

解下列方程!就三道!解下列方程.1、x/x-2 - 1-x²/x²-5x = 2x/x-3(x/x-2 - 1-x²不是一起的!)2、5x/x²+x-6 - 5-2x/x²-x-12=7x-10/x²-6x+8(5x/x²+x-6 - 5-2x不是一起的!)3、x-4/x-5 + x-8/x-9=x-7/x- 请问这道题咋做 :(x)X (x+1) X (x+2) X (x+3) =360 (X-X*20%-18-(X-X*20%-18)*10%=X*1/2-3(过程) x+2x+(x+10)=90,x=? (x/x-2)-2=3(x-2)/x x(2x-3)=x² 求x, (1) 3x-42=9x-2 (2) 2x-5(3-2x)=10 (3) 2(2x+1)-(5x-1)=6 (4)2x+14=28-14x(5)2(x-2)-3(4x-1)=9(1+x)(6)11x+64+2x=100-9x(7)15-(8-5x)=7x+(4-3x)(8)30x-10(10-x)=100 计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1 请问,这5道关于一元一次方程的题目我都做对了吗?(1)8X-3(3X+2)=108x-9x+6=108x-9x=10-6-1x=4X=-4(2) 8X-5(X+2)=68x-5x+10=63x=6-103x=-4X=-1.33(只要小数点后面两位数)(3) 4X+3(2X-3)=15-(X+6)4x+6x-9=15-x-64x+6x+x=9+911x=18X 解方程(x-2)X(x的平方-6x-9)=x(x-5)X(x-3) 解方程:(x-8)/(x-3)-(x-9)/(x-4)=(x+7)/(x+8)-(x+2)/(x+3) 为什么3X-2(-X?(X-1)+5)=-3X +2 X? (X-1)-10 解方程 x(2x-5)=4x-10 x+5x+7=3x+11 (x+1分之x+6)-(x^+3x+2分之3x^+10x+4)+(x+2分之2x+1)=0,解这个方程 (64-2x)(10-x)=558 (32-x)(20-x)=540 60%x+25=40 x+30%x=52 19-120%x=7 4分之3x-5%x=17.5 x-10%x=18 (1-25%)x=36 2x+30%x=9.2 (X-3分之x-1-x分之x-4)除以x的平方+3x分之(x+3)(x-2),其中(x-1)(x-2)=0 设函数f(x)=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10),求f’(1)