将一定量H2S气体通入200ML1MOL/L的NAOH溶液中,充分反应后在低温下蒸发溶液,得到7.92克的白色固体A(1)推测白色固体A所有可能的组成(2)通过计算确定组成A的物质及其质量我觉得化学学起来很麻

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将一定量H2S气体通入200ML1MOL/L的NAOH溶液中,充分反应后在低温下蒸发溶液,得到7.92克的白色固体A(1)推测白色固体A所有可能的组成(2)通过计算确定组成A的物质及其质量我觉得化学学起来很麻

将一定量H2S气体通入200ML1MOL/L的NAOH溶液中,充分反应后在低温下蒸发溶液,得到7.92克的白色固体A(1)推测白色固体A所有可能的组成(2)通过计算确定组成A的物质及其质量我觉得化学学起来很麻
将一定量H2S气体通入200ML1MOL/L的NAOH溶液中,充分反应后在低温下蒸发溶液,得到7.92克的白色固体A
(1)推测白色固体A所有可能的组成
(2)通过计算确定组成A的物质及其质量
我觉得化学学起来很麻烦,要记住那么多的化学方程式和各种沉淀等,记不住题目就做不出来!请问有什么好办法吗!
请问写一大堆英语的,你写的是什么?
fanxiaoxue11 回答得比较完整,如果能回答第二个问题就好了!

将一定量H2S气体通入200ML1MOL/L的NAOH溶液中,充分反应后在低温下蒸发溶液,得到7.92克的白色固体A(1)推测白色固体A所有可能的组成(2)通过计算确定组成A的物质及其质量我觉得化学学起来很麻
(1)如果NaoH 正好完全反应,按反应物的量算,则有
H2S + 4NaOH = 2Na2S + 4H2O
题目中给的是200ML1MOL/L的NAOH 即 0.2mol
那么生成物Na2S的量正好为 0.1mol .即7.8g.显然小于7.92g,就说明除了Na2S,还有别的物质存在.
(2)我们来看另外一种情况,假如NaOH过量,我们按照生成物的量来计算.此时7.92克的白色固体A包括生成的Na2S,还有没有反应完的NaOH.
H2S + 4NaOH = 2Na2S + 4H2O
设 生成的的Na2S为 x mol ,则参加反应的NaOH为 2x mol.那么剩余的量为 (0.2-2x )mol.此时有 (0.2-2x )*40 + x * 78 =7.92
解得 x =0.04mol 即参加反应的NaOH为 0.08 mol .白色固体A组成为 NaOH和Na2S.
(3)还有一种情况即 NaOH 不过量,H2S气体过量,那么反应方程式为
H2S + NaOH =NaHS + H2O
按照NaOH 的量来算,则有 NaHS 0.2mol 即 0.2 * 60=12g 大于7.92g.
所以 此种情况不存在.
故此题的正确解答是白色固体为 白色固体A组成为 NaOH和Na2S.
质量分别为 NaOH:4.8g Na2S:3.12g .
你说的第二种问题是甚么?是你补充的怎么学好化学的那个吗?我想告诉你,化学是一门很有趣的学科.俗话说兴趣是最好的老师,我当时化学好就是因为特别喜欢,看着两种东西加在一起就起了反应,冒了气泡,变了颜色,你不觉得很有意思吗.当然这是我个人所见.化学方程式是化学反应的核心,其实主要就是酸根离子和OH根离子的反应,至于沉淀,化学教材上应该都有说明,甚么甚么是不溶物,沉淀等.你要多用心学习.
还有,你为什么觉得我回答的好,是因为我把解题方法也说明的很清楚,你是不是看了就有种很明了的感觉?就是看完之后觉得这道题就是这个解题思路?是的,我之所以给你写了这么多,把解题步骤给你说的这么详细,第一是想为你解答疑惑,第二就是我本身对化学的热爱,其实解题的过程也是我思考的过程.我觉得这个题就是应该这么解答的,所以一步步的写下来,结果也就跟着出来了.所以告诉你,小弟,也许是小妹,想学好化学,解题思路和方法很重要,这个一下子也说不好,需要你在学习过程中一步步的总结,琢磨.学习.最后我祝你能够取得进步.

(1)NaOH,Na2S
(2)若H2S过量,则Na2S=15.6g
所以其不过量
H2s+2NaOH=Na2S+2H2O
Na+守恒,为0.2mol
即设固体中OH-为Xmol
则17x+16(0.2-x)=7.92-0.2x23
解得:x=0.12
即组成为NaOH:4.8g Na2S:3.12g
化学是一个很零碎的过...

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(1)NaOH,Na2S
(2)若H2S过量,则Na2S=15.6g
所以其不过量
H2s+2NaOH=Na2S+2H2O
Na+守恒,为0.2mol
即设固体中OH-为Xmol
则17x+16(0.2-x)=7.92-0.2x23
解得:x=0.12
即组成为NaOH:4.8g Na2S:3.12g
化学是一个很零碎的过程,因为有很多种特殊情况,比如硫化物中有可溶和不可溶于酸的。。。
大多数有规律可循,双水解反应就是一个例子。阳离子和OH-,阴离子和H+。。
重理解。

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FLUENT bulk cement tanker transportation based on the process flow simulation


q, specific enthalpy; to heat flow; S. Is the enthalpy of facies, such as the chemical reaction; Q is th...

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FLUENT bulk cement tanker transportation based on the process flow simulation


q, specific enthalpy; to heat flow; S. Is the enthalpy of facies, such as the chemical reaction; Q is the intensity of heat exchange between phases; h is the enthalpy and white, such as the process of air temperature in the droplets of water vapor that has enthalpy. These are the two-phase system of control equations to be solved. FLUENT in the application process, the use of dual Euler model to study the fluidization process. Two-phase Eulerian model requires two models can not be compressed, so do not create the energy equation of two-phase system. Therefore, the research process to establish the actual situation in the gas-solid two-phase flows the continuity equation, momentum equation, and the volume fraction equation turbulence equations to solve the problem of fluidized cement tank. 2 cans of streaming flow model to improve computational efficiency, the establishment of a number of two-dimensional fluidized bed process as a characteristic cross-section model. After the geometric symmetry plane position,magasin moncler, Y-shaped air distribution plate minimum cross-section, the middle section and top section are the features section,tory burch shoes, so the cross section were established in these two-dimensional fluidized bed model, shown in Figure 1. Figure 4,Moncler sale,5 a specific location within that section of the line of cement volume fraction of the reference position. Figure 1,moncler jackets, rectangular plate-shaped symmetrical cross-section trellis 2Y 3Y plate-shaped cross-section trellis board rectangular top section of Figure 4 Location of symmetrical cross-section reference line interface reference 5Y-shaped plate line position of the top 3 process flow simulation and results analysis table a numerical calculation of basic data used in FLUENT to cement a double Eulerian model of air to establish two-fluid model. The porous plate and breathable canvas layer to make the compressed air from the intake pipe pressure drop into the chamber evenly distributed throughout the air distribution plate, that the air evenly through the porous plate JJ, ~ L; Moreover, since the camp opened breathable layer relatively large porosity, permeability layer near the hole that was 1. According to conservation of air flow, air flow rate of the process flow is relatively small, the process of the air flow can be considered incompressible. Inflate the actual flow of the process tank, the flow of the tank is closed. This is very difficult to deal with FLUENT,ugg boots billig, the actual establishment of the export model set up to address, this will not fundamentally affect the flow of air on the cement of the results. As the flow of powder material by a certain influence of temperature and pressure, in order to closer to the actual operating conditions, taking the average pressure and average temperature as the flow of the process of boundary conditions. Based on the above assumptions and simplified conditions, a practical process flow of the cement tank model, the boundary conditions shown in Table 1, calculated using discrete solver, transient solution, iterative time step 0.001S, computation time 30s. Of the rectangular plate, for example, the calculation results are shown below. (1) symmetrical rectangular cross-section of cement board changes in the volume fraction of the initial cement volume fraction in Figure 6 State State State State State State State State State State State State State State State tame ‰-_ Perak avoid ● I, not later than 8 PEI such as: transportation of bulk cement tanker based on FLUENT process flow simulation of a 0105e0182e 155.50 e a a 0l60e 0l27e a 『I137e. 0j15e-0192e 0170e-OI47e0125e a 0l02e for a one 0I80e a 0157e. One of a 0ll2e ? 0199e 0135e 0274e 0250e a 0225e for a 0200c +00 Figure 75s when a volume fraction of cement when the cement volume fraction Figure 810s 915s chart diagram 1020s when the volume fraction of cement when the cement volume fraction Figure 1130s when the volume fraction of cement (2) rectangular cement board section of the volume fraction of a specific location l_25m. 75-0.250.250.751.25 a l_25-0.75-0.250.250.751.25 Location / m Location / m Figure l2 points Rectangular Line 1, the cement volume fraction Figure l4 Rectangular Line 3 cement volume fraction of the points chart l3 points Rectangular Line 2 position of the cement volume fraction 0.20.40.60.811.2, m Figure l5 points Rectangular Line 4, the cement volume fraction (3) Air rectangular cross-section of plate the particle velocity vector (30s) Figure l6 rectangular cross-section of the plate number of the air velocity vector using quasi blistering speed discrimination judgments than the minimum flow difficulties. The reason is two-phase system is difficult to directly determine the rate of gas. The numerical results thus required to determine the flow of cement and the cavity flow of fluidization quality. ■ Cuan. Feather fan possession ■ ■ ■ mole tunnel. . Huixia crab ● ● Ⅱ ¨ ¨ children children K ¨ ● ● ● ● ● ● 23 ● ● ■ ● ■ ■ ■ ● ■ Cong tunnel kick
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将一定量的h2s气体通入200ml1mol的naoh溶液.将一定量的H2S气体通入200mL,1mol/L NaOH溶液中,充分反应后在低温下蒸发溶液,得到白色固体A 7.92克.(1)推测白色固体A所有可能的组成 (2)通过计算确 将一定量的h2s气体通入200ml1mol的naoh溶液.充分反应后在低温下蒸发溶液.得7.92克白色固体a,求a的组成和质量 将一定量H2S气体通入200ML1MOL/L的NAOH溶液中,充分反应后在低温下蒸发溶液,得到7.92克的白色固体A(1)推测白色固体A所有可能的组成(2)通过计算确定组成A的物质及其质量我觉得化学学起来很麻 将一定量的h2s气体通入200ml1mol的naoh溶液.充分反应后在低温下蒸发溶液.得7.92克白色固体a的组成请问这个a的组成可能是NaOH+Na2S的混合物吗? 将一定量H2S气体通入200ml1mol/lNaOH溶液中,充分反应后在低温下蒸发溶液,得到7.92g白色固体A1.推测白色固体A所有可能组成2.通过计算确定A物质及质量 向200ml1mol/L的NaOH溶液中通入一定量的H2S气体向200mL1mol每升的NaOH溶液中通入一定量的H2S气体,充分反应后小心将溶液蒸干,称量剩余固体的质量为7.9g,则下列物质一定存在的是( ) .A.NaOH B.Na2S C .NaHS 有关硫化氢 将一定量的H2S气体通入200mL,1mol/L NaOH溶液中,充分反应后在低温下蒸发溶液,得到白色固体A 7.92克.(1)推测白色固体A所有可能的组成(2)通过计算确定组成A的物质及其质量 将一定量的H2S气体通入200mL,1mol/L NaOH溶液中,充分反应后在低温下蒸发溶液,得到白色固体A 7.92克.(1)推测白色固体A所有可能的组成 (2)通过计算确定组成A的物质及其质量 将H2S气体通入CuSO4溶液生成CuS沉淀,能说明H2S是弱电解质吗? 将H2S气体通入酸化的FeSO4为什么没什么现象 将H2S气体通入NAOH溶液中,蒸干后得到的无水物是什么? 关于S的.将一定量的H2S气体缓慢通入300mL0.4mol/L的 NaOH溶液中,然后在减压低温条件下蒸干,得到5.36g固体(不含有结晶水 ) 通过计算判断固体的组成及各组成的物质的量. ———— 一定量甲烷在空气中充分燃烧,产生的气体通入NaOH溶液,一定量甲烷在空气中充分燃烧,产生的气体通入NaOH溶液,充分反应后滴加足量的稀硫酸,将产生的气体通入足量的石灰水,产生沉 常温下,将10mlNO2与一定量的O2通入倒扣在水槽中的试管,充分反映后剩余气体2ml.求O2的体积 将so2通入bacl2溶液中,无沉淀生成,再通入cl2 或 nh3 或 气体h2s 均能产生沉淀 将15.6g Na2O2和5.4g Al同时放入一定量的水中,充分反应后得到200mL溶液,...将15.6g Na2O2和5.4g Al同时放入一定量的水中,充分反应后得到200mL溶液,再向该溶液中缓慢通入标准状况下的HCl气体6.72L.若反 在标准状况下,将3.36L硫化氢气体通入含有一定量氢氧化钠的溶液中全部被吸收,氢氧化钠也全部发生反应.然在标准状况下,将3.36L硫化氢气体通入含有一定量氢氧化钠的溶液中全部被吸收,氢 将一定量的炭和氧气放入一密闭容器中燃烧,待氧气耗尽时,得到10g气体.将该气体通入足量的澄清石灰水后,(接上)气体剩余5.6g.计算:(1)炭燃烧生成二氧化碳的质量(2)气体通入石灰水