f(x)sin^4x+cos^4x-1/sin(3π/2+x)cos(3π/2-x)的奇偶性

已知f(x)=cos^2x/1+sin^2x求f'(π/4)求导 f'(sin x)=1-cos x 求f''(x) 函数f(x)=2sin(π/4-x)×cos(π/4+x)-1化简 求f(x)=1/sin²x+4/cos²x的最小值 求函数f(x)=1/sin²x +4/cos²x的最小值 已知函数f(x)=sin²(π/4+x)+cos²x+1/2求最值 化简f(x)=(1-√2*cos(2x-π/4))/sin(π/2-x) f x =sin(pai*x/4-pai/6)-2(cos pai*x/8)^2+1 化简f(x)=(1+√2*cos(2x-π/4))/sin(π/2-x) f(x)=(6sin^4x-7sin^2x+2)/(sin^2x-cos^2x) f(x)=sin(x+π/4)图像怎样变成F(x)=cos(2x) 化简 1-sin^4x-cos^4x/1-sin^6x-cos^6x 化简(1-cos^4x-sin^4x)/(1-cos^6x-sin^6x) 求值：(1-sin^6 x-cos^6 x)/(1-sin^4 x-cos^4 x) 求证（cos^2 x-sin^2 x)(cos^4 x+sin^4 x)+1/4 sin 2x sin 4x=cos 2x f(x)sin^4x+cos^4x-1/sin(3π/2+x)cos(3π/2-x)的奇偶性 设f(sin x/2 )-1+cos x ,求f(x)、f(cos x/2 ). 已知函数f(x)=cos^4x-2sinxcosx-sin^4x(1)求f(x)的最小正周期(2)当x∈【0,π/2】时,求f(x)的最小值以及取得最小值时x的集合f(x)=cos^4x-2sinxcosx-sin^4x=cos^4x-sin^4x-2sinxcosx=(cos^2x+sin^2x)(cos^2x-sin^2x)-2sinxcosx我做到