设F1(x)=sin3x,Fn+1(x)=F'n(x) (n为正整数),求Fn(x)?

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设F1(x)=sin3x,Fn+1(x)=F'n(x)   (n为正整数),求Fn(x)?

设F1(x)=sin3x,Fn+1(x)=F'n(x) (n为正整数),求Fn(x)?
设F1(x)=sin3x,Fn+1(x)=F'n(x) (n为正整数),求Fn(x)?

设F1(x)=sin3x,Fn+1(x)=F'n(x) (n为正整数),求Fn(x)?
由an=[fn(0)-1]/[fn(0)+2]算出fn(0)=3/(1-an)-2 此为1式则f(n+1)(0)=3/(1-a(n+1))-2 因为f(n+1)(x)=f1[fn(x)] 所以f

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