求初值：dy/dx+y/x=x+1/x,当x=2,y=3

求初值：dy/dx+y/x=x+1/x,当x=2,y=3 求微分方程初值y^3d^2y/dx^2+1=0,y|x=1=1,dy/dx|x=1=0 求微分方程dy/dx-2xy=e^x^2cosx满足初值条件y(0)=1的解 设y=（x/1-x)^x,求dy/dx 请问用matlab怎么编程这个微分方程啊dy/dx=y-2*x/y,初值是y(0)=1.求y(1) ,急 (dy/dx)-y=x求微分方程 y=(sinx)^x 求DY/DX y=x+lnx,求dx/dy 求dy/dx= - x/y matlab 龙格库塔法求解微分方程dy/dx)=y^2+x,初值为x(0)=5 ,y(0)=2 y=f[(x-1)/(x+1)],f'(x)=arctanx^2,求dy/dx,dy 已知y=x^(1/y),求dy/dx? dy/dx=x+y 求微分方程y－dy／dx=1＋x×dy／dx的通解 dy/dx=-x/y 求通解如题.dy/dx=-x/y 求通解 dy/dx=1+1/(x-y) dy/dx=1-cos(y-x) dy/dx=x(1-y)