a^[log(a)b×log(b)c×log(c)N]求值

1≤a≤b≤c,证明log(a)(b)+log(b)(c)+log(c)(a)≤log(b)(a)+log(c)(b)+log(a)(c) log(a)(b)=log(c)(b) /log(c)(a) 怎么证log(a)(b)=log(c)(b) /log(c)(a)怎么证 log(a)(b)+log(a)(c)可以等于什么 log(a)b=log(c)b/log(c)a 是怎么推算来的 a^[log(a)b×log(b)c×log(c)N]求值 求对数的解答题!求值.log(b)A*log(c)B*log(a)C 2log(b)x=log(a)x+log(c)x求证,c^2=(ac)^[log(a)b] 对数函数题 log a - log b = 3 log (c/2) 求 a = ______________ log a b*log b c=log b b*log a c成立吗中间的字母是写在下面的 相当于log的脚码 loga(b)×log(a)c＝? 已知01,则下列不等式中成立的是（ ）A.log(b)(1/b)＜log(a)(b)＜log(a)(1/b)B.log(a)(b)＜log(b)(1/b)＜log(a)(1/b)C.log(a)(b)＜log(a)(1/b)＜log(b)(1/b)D.log(b)(1/b)＜log(a)(1/b)＜log(a)(b) 利用换底公式证明：log(a)b.log(b)c.log(c)a=1rt.是乘号 log a b=log c b/log c a 这个定理是怎么用定义推导出来的 logab为什么等于logcb/logcalog a B=log c B / log c A 求证明 a^(log(c)(b))=b(log(c)(a)) 27-1/ 若a>0,b>0,a*b>1,log(1/2)[a]=ln2,则log(a)[b]与log(1/2)[a]的关系是：（）?(A)log(a)b< log(1/2)[a](B)log(a)b= log(1/2)[a](C)log(a)b>log(1/2)[a](D)log(a)b与log(1/2)[a] 无法比较大小我做到一半就做不下去了：a=(1/2)^(ln2)log 已知a、b、c为直角三角形三边,c为斜边.log(a+b)+log(c-b)=2log(b+c)alog(c-b)a括号内均为底数 已知a、b、c为直角三角形三边，c为斜边。证明：log(a+b)a+log(c-b)a=2log(b+c)a·log(c-b)a 化简log(1/a)b+log(a)b